In a pouch of notes, the number of $10, $50 and $100 are in ratio of 3 : 4 : 6.
23 of the $10-notes is taken out and another 10 $50-notes are added. The remaining notes are worth $8600. Find the difference between the value of $100-notes and $10-notes in the end.
| |
$10 |
$50 |
$100 |
| Before |
3 u |
4 u |
6 u |
| Change |
- 2 u |
+ 10 |
|
| After |
1 u |
4 u + 10 |
6 u |
| |
$10 |
$50 |
$100 |
Total |
| Number |
1 u |
4 u + 10 |
6 u |
|
| Value |
10 |
50 |
100 |
|
| Total value |
10 u |
200 u + 500 |
600 u |
8600 |
Total value of the notes
= 10 u + 200 u + 500 + 600 u
= 810 u + 500
810 u + 500 = 8600
810 u = 8600 - 500
810 u = 8100
1 u = 8100 ÷ 810 = 10
Difference between the value of $100-notes and $10-notes in the end
= 600 u - 10 u
= 590 u
= 590 x 10
= $5900
Answer(s): $5900
