In a bag of notes, the number of $2, $10 and $50 are in ratio of 7 : 6 : 5.
47 of the $2-notes is taken out and another 4 $10-notes are added. The remaining notes are worth $988. Find the difference between the value of $50-notes and $2-notes in the end.
| |
$2 |
$10 |
$50 |
| Before |
7 u |
6 u |
5 u |
| Change |
- 4 u |
+ 4 |
|
| After |
3 u |
6 u + 4 |
5 u |
| |
$2 |
$10 |
$50 |
Total |
| Number |
3 u |
6 u + 4 |
5 u |
|
| Value |
2 |
10 |
50 |
|
| Total value |
6 u |
60 u + 40 |
250 u |
988 |
Total value of the notes
= 6 u + 60 u + 40 + 250 u
= 316 u + 40
316 u + 40 = 988
316 u = 988 - 40
316 u = 948
1 u = 948 ÷ 316 = 3
Difference between the value of $50-notes and $2-notes in the end
= 250 u - 6 u
= 244 u
= 244 x 3
= $732
Answer(s): $732
