There were some children in a stadium.
14 of the children lined up in 10 long rows and
16 of the children lined up in 6 short rows. The remaining children did not line up. There are 6 more children in each short row than each long row.
(a) What fraction of the children did not line up?
(b) How many children lined up?
|
Long rows |
Short rows |
Number |
10 |
6 |
Value |
1 u |
1 u + 6 |
Total value |
10 u |
6 u + 36 |
(a)
Fraction of children who did not line up
= 1 -
14 -
16 = 1 -
312 -
212= 1 -
512=
712(b)
312 of the children lined up in long rows.
10 u = 3 p --- (1)
212 of the children lined up in short rows.
6 u + 36 = 2 p --- (2)
(1)
x2
20 u = 6 p --- (3)
(2)
x3
18 u + 108 = 6 p --- (4)
(3) = (4)
20 u = 18 u + 108
20 u - 18 u = 108
2 u = 108
1 u = 108 ÷ 2 = 54
Number of children who lined up
= 10 u + 6 u + 36
= 16 u + 36
= 864 + 36
= 900
Answer(s): (a)
712; (b) 900