There were some children in a tourist attraction.
14 of the children lined up in 8 short rows and
15 of the children lined up in 4 long rows. The remaining children did not line up. There are 6 more children in each long row than each short row.
(a) What fraction of the children did not line up?
(b) How many children lined up?
|
Short rows |
Long rows |
Number |
8 |
4 |
Value |
1 u |
1 u + 6 |
Total value |
8 u |
4 u + 24 |
(a)
Fraction of children who did not line up
= 1 -
14 -
15 = 1 -
520 -
420= 1 -
920=
1120(b)
520 of the children lined up in short rows.
8 u = 5 p --- (1)
420 of the children lined up in long rows.
4 u + 24 = 4 p --- (2)
(1)
x4
32 u = 20 p --- (3)
(2)
x5
20 u + 120 = 20 p --- (4)
(3) = (4)
32 u = 20 u + 120
32 u - 20 u = 120
12 u = 120
1 u = 120 ÷ 12 = 10
Number of children who lined up
= 8 u + 4 u + 24
= 12 u + 24
= 120 + 24
= 144
Answer(s): (a)
1120; (b) 144