There were some children in a safari park.
14 of the children lined up in 10 short rows and
16 of the children lined up in 6 long rows. The remaining children did not line up. There are 10 more children in each long row than each short row.
(a) What fraction of the children did not line up?
(b) How many children lined up?
|
Short rows |
Long rows |
Number |
10 |
6 |
Value |
1 u |
1 u + 10 |
Total value |
10 u |
6 u + 60 |
(a)
Fraction of children who did not line up
= 1 -
14 -
16 = 1 -
312 -
212= 1 -
512=
712(b)
312 of the children lined up in short rows.
10 u = 3 p --- (1)
212 of the children lined up in long rows.
6 u + 60 = 2 p --- (2)
(1)
x2
20 u = 6 p --- (3)
(2)
x3
18 u + 180 = 6 p --- (4)
(3) = (4)
20 u = 18 u + 180
20 u - 18 u = 180
2 u = 180
1 u = 180 ÷ 2 = 90
Number of children who lined up
= 10 u + 6 u + 60
= 16 u + 60
= 1440 + 60
= 1500
Answer(s): (a)
712; (b) 1500