Julie and Linda have some wafers each. If Julie gives Linda 18 wafers, Julie will have
29 as many wafers as Linda. If Julie gives Linda 15 wafers, they will have an equal number of wafers. How many wafers does Julie have at first?
|
Case 1 |
Case 2 |
|
Julie |
Linda |
Julie |
Linda |
Before |
2 u + 18 |
9 u - 18 |
5.5 u + 15 |
5.5 u - 15 |
Change |
- 18 |
+ 18 |
- 15 |
+ 15 |
After |
2 u |
9 u |
5.5 u |
5.5 u |
Total number of wafers that Julie and Linda have
= 2 u + 9 u
= 11 u
Number of wafers that Julie and Linda each has in the end is the same.
Number of wafers that Julie and Linda each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of wafers that Julie had at first is the same in Case 1 and Case 2.
5.5 u + 15 = 2 u + 18
5.5 u - 2 u = 18 - 15
0.5 u = 3
1 u = 3 ÷ 0.5 = 6
Number of wafers that Julie has
= 2 u + 18
= 2 x 6 + 18
= 12 + 18
= 30
Answer(s): 30