Jean and Vanessa have some biscuits each. If Jean gives Vanessa 25 biscuits, Jean will have
23 as many biscuits as Vanessa. If Jean gives Vanessa 19 biscuits, they will have an equal number of biscuits. How many biscuits does Jean have at first?
|
Case 1 |
Case 2 |
|
Jean |
Vanessa |
Jean |
Vanessa |
Before |
2 u + 25 |
3 u - 25 |
2.5 u + 19 |
2.5 u - 19 |
Change |
- 25 |
+ 25 |
- 19 |
+ 19 |
After |
2 u |
3 u |
2.5 u |
2.5 u |
Total number of biscuits that Jean and Vanessa have
= 2 u + 3 u
= 5 u
Number of biscuits that Jean and Vanessa each has in the end is the same.
Number of biscuits that Jean and Vanessa each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u
Number of biscuits that Jean had at first is the same in Case 1 and Case 2.
2.5 u + 19 = 2 u + 25
2.5 u - 2 u = 25 - 19
0.5 u = 6
1 u = 6 ÷ 0.5 = 12
Number of biscuits that Jean has
= 2 u + 25
= 2 x 12 + 25
= 24 + 25
= 49
Answer(s): 49