Shannon and Jean have some tarts each. If Shannon gives Jean 23 tarts, Shannon will have ¹₂ as many tarts as Jean. If Shannon gives Jean 10 tarts, they will have an equal number of tarts. How many tarts does Jean have at first?

	Case 1		Case 2
	Shannon	Jean	Shannon	Jean
Before	1 u + 23	2 u - 23	1.5 u + 10	1.5 u - 10
Change	- 23	+ 23	- 10	+ 10
After	1 u	2 u	1.5 u	1.5 u

Total number of tarts that Shannon and Jean have
= 1 u + 2 u
= 3 u 

Number of tarts that Shannon and Jean each has in the end is the same.

Number of tarts that Shannon and Jean each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u

Number of tarts that Shannon had at first is the same in Case 1 and Case 2.

1.5 u + 10 = 1 u + 23
1.5 u - 1 u = 23 - 10
0.5 u = 13

1 u = 13 ÷ 0.5 = 26

Number of tarts that Jean has
= 2 u - 23
= 2 x 26 - 23
= 52 - 23
= 29

Answer(s): 29