Xandra and Esther have some wafers each. If Xandra gives Esther 11 wafers, Xandra will have
12 as many wafers as Esther. If Xandra gives Esther 2 wafers, they will have an equal number of wafers. How many wafers does Xandra have at first?
|
Case 1 |
Case 2 |
|
Xandra |
Esther |
Xandra |
Esther |
Before |
1 u + 11 |
2 u - 11 |
1.5 u + 2 |
1.5 u - 2 |
Change |
- 11 |
+ 11 |
- 2 |
+ 2 |
After |
1 u |
2 u |
1.5 u |
1.5 u |
Total number of wafers that Xandra and Esther have
= 1 u + 2 u
= 3 u
Number of wafers that Xandra and Esther each has in the end is the same.
Number of wafers that Xandra and Esther each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u
Number of wafers that Xandra had at first is the same in Case 1 and Case 2.
1.5 u + 2 = 1 u + 11
1.5 u - 1 u = 11 - 2
0.5 u = 9
1 u = 9 ÷ 0.5 = 18
Number of wafers that Xandra has
= 1 u + 11
= 1 x 18 + 11
= 18 + 11
= 29
Answer(s): 29