Natalie and Hilda have some macarons each. If Natalie gives Hilda 20 macarons, Natalie will have
23 as many macarons as Hilda. If Natalie gives Hilda 10 macarons, they will have an equal number of macarons. How many macarons does Natalie have at first?
|
Case 1 |
Case 2 |
|
Natalie |
Hilda |
Natalie |
Hilda |
Before |
2 u + 20 |
3 u - 20 |
2.5 u + 10 |
2.5 u - 10 |
Change |
- 20 |
+ 20 |
- 10 |
+ 10 |
After |
2 u |
3 u |
2.5 u |
2.5 u |
Total number of macarons that Natalie and Hilda have
= 2 u + 3 u
= 5 u
Number of macarons that Natalie and Hilda each has in the end is the same.
Number of macarons that Natalie and Hilda each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u
Number of macarons that Natalie had at first is the same in Case 1 and Case 2.
2.5 u + 10 = 2 u + 20
2.5 u - 2 u = 20 - 10
0.5 u = 10
1 u = 10 ÷ 0.5 = 20
Number of macarons that Natalie has
= 2 u + 20
= 2 x 20 + 20
= 40 + 20
= 60
Answer(s): 60