Elyse and Sarah have some wafers each. If Elyse gives Sarah 36 wafers, Elyse will have ³₄ as many wafers as Sarah. If Elyse gives Sarah 9 wafers, they will have an equal number of wafers. How many wafers does Sarah have at first?

	Case 1		Case 2
	Elyse	Sarah	Elyse	Sarah
Before	3 u + 36	4 u - 36	3.5 u + 9	3.5 u - 9
Change	- 36	+ 36	- 9	+ 9
After	3 u	4 u	3.5 u	3.5 u

Total number of wafers that Elyse and Sarah have
= 3 u + 4 u
= 7 u 

Number of wafers that Elyse and Sarah each has in the end is the same.

Number of wafers that Elyse and Sarah each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u

Number of wafers that Elyse had at first is the same in Case 1 and Case 2.

3.5 u + 9 = 3 u + 36
3.5 u - 3 u = 36 - 9
0.5 u = 27

1 u = 27 ÷ 0.5 = 54

Number of wafers that Sarah has
= 4 u - 36
= 4 x 54 - 36
= 216 - 36
= 180

Answer(s): 180