Nicole and Eva have some macarons each. If Nicole gives Eva 19 macarons, Nicole will have
38 as many macarons as Eva. If Nicole gives Eva 9 macarons, they will have an equal number of macarons. How many macarons does Nicole have at first?
|
Case 1 |
Case 2 |
|
Nicole |
Eva |
Nicole |
Eva |
Before |
3 u + 19 |
8 u - 19 |
5.5 u + 9 |
5.5 u - 9 |
Change |
- 19 |
+ 19 |
- 9 |
+ 9 |
After |
3 u |
8 u |
5.5 u |
5.5 u |
Total number of macarons that Nicole and Eva have
= 3 u + 8 u
= 11 u
Number of macarons that Nicole and Eva each has in the end is the same.
Number of macarons that Nicole and Eva each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of macarons that Nicole had at first is the same in Case 1 and Case 2.
5.5 u + 9 = 3 u + 19
5.5 u - 3 u = 19 - 9
0.5 u = 10
1 u = 10 ÷ 0.5 = 20
Number of macarons that Nicole has
= 3 u + 19
= 3 x 20 + 19
= 60 + 19
= 79
Answer(s): 79