Zoe and Xylia have some shortbreads each. If Zoe gives Xylia 25 shortbreads, Zoe will have
25 as many shortbreads as Xylia. If Zoe gives Xylia 4 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Xylia have at first?
|
Case 1 |
Case 2 |
|
Zoe |
Xylia |
Zoe |
Xylia |
Before |
2 u + 25 |
5 u - 25 |
3.5 u + 4 |
3.5 u - 4 |
Change |
- 25 |
+ 25 |
- 4 |
+ 4 |
After |
2 u |
5 u |
3.5 u |
3.5 u |
Total number of shortbreads that Zoe and Xylia have
= 2 u + 5 u
= 7 u
Number of shortbreads that Zoe and Xylia each has in the end is the same.
Number of shortbreads that Zoe and Xylia each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u
Number of shortbreads that Zoe had at first is the same in Case 1 and Case 2.
3.5 u + 4 = 2 u + 25
3.5 u - 2 u = 25 - 4
0.5 u = 21
1 u = 21 ÷ 0.5 = 42
Number of shortbreads that Xylia has
= 5 u - 25
= 5 x 42 - 25
= 210 - 25
= 185
Answer(s): 185