Gillian and Dana have some biscuits each. If Gillian gives Dana 22 biscuits, Gillian will have ³₈ as many biscuits as Dana. If Gillian gives Dana 4 biscuits, they will have an equal number of biscuits. How many biscuits does Dana have at first?

	Case 1		Case 2
	Gillian	Dana	Gillian	Dana
Before	3 u + 22	8 u - 22	5.5 u + 4	5.5 u - 4
Change	- 22	+ 22	- 4	+ 4
After	3 u	8 u	5.5 u	5.5 u

Total number of biscuits that Gillian and Dana have
= 3 u + 8 u
= 11 u 

Number of biscuits that Gillian and Dana each has in the end is the same.

Number of biscuits that Gillian and Dana each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u

Number of biscuits that Gillian had at first is the same in Case 1 and Case 2.

5.5 u + 4 = 3 u + 22
5.5 u - 3 u = 22 - 4
0.5 u = 18

1 u = 18 ÷ 0.5 = 36

Number of biscuits that Dana has
= 8 u - 22
= 8 x 36 - 22
= 288 - 22
= 266

Answer(s): 266