Tammy and Jaslyn have some biscuits each. If Tammy gives Jaslyn 30 biscuits, Tammy will have ²₃ as many biscuits as Jaslyn. If Tammy gives Jaslyn 7 biscuits, they will have an equal number of biscuits. How many biscuits does Jaslyn have at first?

	Case 1		Case 2
	Tammy	Jaslyn	Tammy	Jaslyn
Before	2 u + 30	3 u - 30	2.5 u + 7	2.5 u - 7
Change	- 30	+ 30	- 7	+ 7
After	2 u	3 u	2.5 u	2.5 u

Total number of biscuits that Tammy and Jaslyn have
= 2 u + 3 u
= 5 u 

Number of biscuits that Tammy and Jaslyn each has in the end is the same.

Number of biscuits that Tammy and Jaslyn each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u

Number of biscuits that Tammy had at first is the same in Case 1 and Case 2.

2.5 u + 7 = 2 u + 30
2.5 u - 2 u = 30 - 7
0.5 u = 23

1 u = 23 ÷ 0.5 = 46

Number of biscuits that Jaslyn has
= 3 u - 30
= 3 x 46 - 30
= 138 - 30
= 108

Answer(s): 108