Abi and Jade have some biscuits each. If Abi gives Jade 16 biscuits, Abi will have
34 as many biscuits as Jade. If Abi gives Jade 8 biscuits, they will have an equal number of biscuits. How many biscuits does Abi have at first?
| |
Case 1 |
Case 2 |
| |
Abi |
Jade |
Abi |
Jade |
| Before |
3 u + 16 |
4 u - 16 |
3.5 u + 8 |
3.5 u - 8 |
| Change |
- 16 |
+ 16 |
- 8 |
+ 8 |
| After |
3 u |
4 u |
3.5 u |
3.5 u |
Total number of biscuits that Abi and Jade have
= 3 u + 4 u
= 7 u
Number of biscuits that Abi and Jade each has in the end is the same.
Number of biscuits that Abi and Jade each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u
Number of biscuits that Abi had at first is the same in Case 1 and Case 2.
3.5 u + 8 = 3 u + 16
3.5 u - 3 u = 16 - 8
0.5 u = 8
1 u = 8 ÷ 0.5 = 16
Number of biscuits that Abi has
= 3 u + 16
= 3 x 16 + 16
= 48 + 16
= 64
Answer(s): 64
