Tiffany and Xylia have some shortbreads each. If Tiffany gives Xylia 34 shortbreads, Tiffany will have
18 as many shortbreads as Xylia. If Tiffany gives Xylia 10 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Xylia have at first?
|
Case 1 |
Case 2 |
|
Tiffany |
Xylia |
Tiffany |
Xylia |
Before |
1 u + 34 |
8 u - 34 |
4.5 u + 10 |
4.5 u - 10 |
Change |
- 34 |
+ 34 |
- 10 |
+ 10 |
After |
1 u |
8 u |
4.5 u |
4.5 u |
Total number of shortbreads that Tiffany and Xylia have
= 1 u + 8 u
= 9 u
Number of shortbreads that Tiffany and Xylia each has in the end is the same.
Number of shortbreads that Tiffany and Xylia each has in the end in Case 2
= 9 u ÷ 2
= 4.5 u
Number of shortbreads that Tiffany had at first is the same in Case 1 and Case 2.
4.5 u + 10 = 1 u + 34
4.5 u - 1 u = 34 - 10
0.5 u = 24
1 u = 24 ÷ 0.5 = 48
Number of shortbreads that Xylia has
= 8 u - 34
= 8 x 48 - 34
= 384 - 34
= 350
Answer(s): 350