Zoe and Nora have some croissants each. If Zoe gives Nora 34 croissants, Zoe will have
56 as many croissants as Nora. If Zoe gives Nora 6 croissants, they will have an equal number of croissants. How many croissants does Nora have at first?
|
Case 1 |
Case 2 |
|
Zoe |
Nora |
Zoe |
Nora |
Before |
5 u + 34 |
6 u - 34 |
5.5 u + 6 |
5.5 u - 6 |
Change |
- 34 |
+ 34 |
- 6 |
+ 6 |
After |
5 u |
6 u |
5.5 u |
5.5 u |
Total number of croissants that Zoe and Nora have
= 5 u + 6 u
= 11 u
Number of croissants that Zoe and Nora each has in the end is the same.
Number of croissants that Zoe and Nora each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of croissants that Zoe had at first is the same in Case 1 and Case 2.
5.5 u + 6 = 5 u + 34
5.5 u - 5 u = 34 - 6
0.5 u = 28
1 u = 28 ÷ 0.5 = 56
Number of croissants that Nora has
= 6 u - 34
= 6 x 56 - 34
= 336 - 34
= 302
Answer(s): 302