Roshel and Wendy have some biscuits each. If Roshel gives Wendy 12 biscuits, Roshel will have ²₉ as many biscuits as Wendy. If Roshel gives Wendy 3 biscuits, they will have an equal number of biscuits. How many biscuits does Roshel have at first?

	Case 1		Case 2
	Roshel	Wendy	Roshel	Wendy
Before	2 u + 12	9 u - 12	5.5 u + 3	5.5 u - 3
Change	- 12	+ 12	- 3	+ 3
After	2 u	9 u	5.5 u	5.5 u

Total number of biscuits that Roshel and Wendy have
= 2 u + 9 u
= 11 u 

Number of biscuits that Roshel and Wendy each has in the end is the same.

Number of biscuits that Roshel and Wendy each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u

Number of biscuits that Roshel had at first is the same in Case 1 and Case 2.

5.5 u + 3 = 2 u + 12
5.5 u - 2 u = 12 - 3
0.5 u = 9

1 u = 9 ÷ 0.5 = 18

Number of biscuits that Roshel has
= 2 u + 12
= 2 x 18 + 12
= 36 + 12
= 48

Answer(s): 48