Min and Vanessa have some shortbreads each. If Min gives Vanessa 20 shortbreads, Min will have
67 as many shortbreads as Vanessa. If Min gives Vanessa 14 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Min have at first?
|
Case 1 |
Case 2 |
|
Min |
Vanessa |
Min |
Vanessa |
Before |
6 u + 20 |
7 u - 20 |
6.5 u + 14 |
6.5 u - 14 |
Change |
- 20 |
+ 20 |
- 14 |
+ 14 |
After |
6 u |
7 u |
6.5 u |
6.5 u |
Total number of shortbreads that Min and Vanessa have
= 6 u + 7 u
= 13 u
Number of shortbreads that Min and Vanessa each has in the end is the same.
Number of shortbreads that Min and Vanessa each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u
Number of shortbreads that Min had at first is the same in Case 1 and Case 2.
6.5 u + 14 = 6 u + 20
6.5 u - 6 u = 20 - 14
0.5 u = 6
1 u = 6 ÷ 0.5 = 12
Number of shortbreads that Min has
= 6 u + 20
= 6 x 12 + 20
= 72 + 20
= 92
Answer(s): 92