Cindy and Roshel have some shortbreads each. If Cindy gives Roshel 14 shortbreads, Cindy will have ⁵₆ as many shortbreads as Roshel. If Cindy gives Roshel 5 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Cindy have at first?

	Case 1		Case 2
	Cindy	Roshel	Cindy	Roshel
Before	5 u + 14	6 u - 14	5.5 u + 5	5.5 u - 5
Change	- 14	+ 14	- 5	+ 5
After	5 u	6 u	5.5 u	5.5 u

Total number of shortbreads that Cindy and Roshel have
= 5 u + 6 u
= 11 u 

Number of shortbreads that Cindy and Roshel each has in the end is the same.

Number of shortbreads that Cindy and Roshel each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u

Number of shortbreads that Cindy had at first is the same in Case 1 and Case 2.

5.5 u + 5 = 5 u + 14
5.5 u - 5 u = 14 - 5
0.5 u = 9

1 u = 9 ÷ 0.5 = 18

Number of shortbreads that Cindy has
= 5 u + 14
= 5 x 18 + 14
= 90 + 14
= 104

Answer(s): 104