Raeann and Abi have some cookies each. If Raeann gives Abi 18 cookies, Raeann will have ²₇ as many cookies as Abi. If Raeann gives Abi 8 cookies, they will have an equal number of cookies. How many cookies does Raeann have at first?

	Case 1		Case 2
	Raeann	Abi	Raeann	Abi
Before	2 u + 18	7 u - 18	4.5 u + 8	4.5 u - 8
Change	- 18	+ 18	- 8	+ 8
After	2 u	7 u	4.5 u	4.5 u

Total number of cookies that Raeann and Abi have
= 2 u + 7 u
= 9 u 

Number of cookies that Raeann and Abi each has in the end is the same.

Number of cookies that Raeann and Abi each has in the end in Case 2
= 9 u ÷ 2
= 4.5 u

Number of cookies that Raeann had at first is the same in Case 1 and Case 2.

4.5 u + 8 = 2 u + 18
4.5 u - 2 u = 18 - 8
0.5 u = 10

1 u = 10 ÷ 0.5 = 20

Number of cookies that Raeann has
= 2 u + 18
= 2 x 20 + 18
= 40 + 18
= 58

Answer(s): 58