Tammy and Yoko have some biscuits each. If Tammy gives Yoko 35 biscuits, Tammy will have ²₃ as many biscuits as Yoko. If Tammy gives Yoko 9 biscuits, they will have an equal number of biscuits. How many biscuits does Yoko have at first?

	Case 1		Case 2
	Tammy	Yoko	Tammy	Yoko
Before	2 u + 35	3 u - 35	2.5 u + 9	2.5 u - 9
Change	- 35	+ 35	- 9	+ 9
After	2 u	3 u	2.5 u	2.5 u

Total number of biscuits that Tammy and Yoko have
= 2 u + 3 u
= 5 u 

Number of biscuits that Tammy and Yoko each has in the end is the same.

Number of biscuits that Tammy and Yoko each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u

Number of biscuits that Tammy had at first is the same in Case 1 and Case 2.

2.5 u + 9 = 2 u + 35
2.5 u - 2 u = 35 - 9
0.5 u = 26

1 u = 26 ÷ 0.5 = 52

Number of biscuits that Yoko has
= 3 u - 35
= 3 x 52 - 35
= 156 - 35
= 121

Answer(s): 121