Yoko and Kylie have some shortbreads each. If Yoko gives Kylie 27 shortbreads, Yoko will have
12 as many shortbreads as Kylie. If Yoko gives Kylie 10 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Kylie have at first?
|
Case 1 |
Case 2 |
|
Yoko |
Kylie |
Yoko |
Kylie |
Before |
1 u + 27 |
2 u - 27 |
1.5 u + 10 |
1.5 u - 10 |
Change |
- 27 |
+ 27 |
- 10 |
+ 10 |
After |
1 u |
2 u |
1.5 u |
1.5 u |
Total number of shortbreads that Yoko and Kylie have
= 1 u + 2 u
= 3 u
Number of shortbreads that Yoko and Kylie each has in the end is the same.
Number of shortbreads that Yoko and Kylie each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u
Number of shortbreads that Yoko had at first is the same in Case 1 and Case 2.
1.5 u + 10 = 1 u + 27
1.5 u - 1 u = 27 - 10
0.5 u = 17
1 u = 17 ÷ 0.5 = 34
Number of shortbreads that Kylie has
= 2 u - 27
= 2 x 34 - 27
= 68 - 27
= 41
Answer(s): 41