Kimberly and Joelle have some tarts each. If Kimberly gives Joelle 24 tarts, Kimberly will have
14 as many tarts as Joelle. If Kimberly gives Joelle 6 tarts, they will have an equal number of tarts. How many tarts does Joelle have at first?
|
Case 1 |
Case 2 |
|
Kimberly |
Joelle |
Kimberly |
Joelle |
Before |
1 u + 24 |
4 u - 24 |
2.5 u + 6 |
2.5 u - 6 |
Change |
- 24 |
+ 24 |
- 6 |
+ 6 |
After |
1 u |
4 u |
2.5 u |
2.5 u |
Total number of tarts that Kimberly and Joelle have
= 1 u + 4 u
= 5 u
Number of tarts that Kimberly and Joelle each has in the end is the same.
Number of tarts that Kimberly and Joelle each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u
Number of tarts that Kimberly had at first is the same in Case 1 and Case 2.
2.5 u + 6 = 1 u + 24
2.5 u - 1 u = 24 - 6
0.5 u = 18
1 u = 18 ÷ 0.5 = 36
Number of tarts that Joelle has
= 4 u - 24
= 4 x 36 - 24
= 144 - 24
= 120
Answer(s): 120