Nicole and Tina have some macarons each. If Nicole gives Tina 10 macarons, Nicole will have
38 as many macarons as Tina. If Nicole gives Tina 2 macarons, they will have an equal number of macarons. How many macarons does Nicole have at first?
|
Case 1 |
Case 2 |
|
Nicole |
Tina |
Nicole |
Tina |
Before |
3 u + 10 |
8 u - 10 |
5.5 u + 2 |
5.5 u - 2 |
Change |
- 10 |
+ 10 |
- 2 |
+ 2 |
After |
3 u |
8 u |
5.5 u |
5.5 u |
Total number of macarons that Nicole and Tina have
= 3 u + 8 u
= 11 u
Number of macarons that Nicole and Tina each has in the end is the same.
Number of macarons that Nicole and Tina each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of macarons that Nicole had at first is the same in Case 1 and Case 2.
5.5 u + 2 = 3 u + 10
5.5 u - 3 u = 10 - 2
0.5 u = 8
1 u = 8 ÷ 0.5 = 16
Number of macarons that Nicole has
= 3 u + 10
= 3 x 16 + 10
= 48 + 10
= 58
Answer(s): 58