Vanessa and Linda have some croissants each. If Vanessa gives Linda 19 croissants, Vanessa will have
38 as many croissants as Linda. If Vanessa gives Linda 16 croissants, they will have an equal number of croissants. How many croissants does Vanessa have at first?
|
Case 1 |
Case 2 |
|
Vanessa |
Linda |
Vanessa |
Linda |
Before |
3 u + 19 |
8 u - 19 |
5.5 u + 16 |
5.5 u - 16 |
Change |
- 19 |
+ 19 |
- 16 |
+ 16 |
After |
3 u |
8 u |
5.5 u |
5.5 u |
Total number of croissants that Vanessa and Linda have
= 3 u + 8 u
= 11 u
Number of croissants that Vanessa and Linda each has in the end is the same.
Number of croissants that Vanessa and Linda each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of croissants that Vanessa had at first is the same in Case 1 and Case 2.
5.5 u + 16 = 3 u + 19
5.5 u - 3 u = 19 - 16
0.5 u = 3
1 u = 3 ÷ 0.5 = 6
Number of croissants that Vanessa has
= 3 u + 19
= 3 x 6 + 19
= 18 + 19
= 37
Answer(s): 37