Barbara and Emily have some croissants each. If Barbara gives Emily 19 croissants, Barbara will have
12 as many croissants as Emily. If Barbara gives Emily 14 croissants, they will have an equal number of croissants. How many croissants does Barbara have at first?
|
Case 1 |
Case 2 |
|
Barbara |
Emily |
Barbara |
Emily |
Before |
1 u + 19 |
2 u - 19 |
1.5 u + 14 |
1.5 u - 14 |
Change |
- 19 |
+ 19 |
- 14 |
+ 14 |
After |
1 u |
2 u |
1.5 u |
1.5 u |
Total number of croissants that Barbara and Emily have
= 1 u + 2 u
= 3 u
Number of croissants that Barbara and Emily each has in the end is the same.
Number of croissants that Barbara and Emily each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u
Number of croissants that Barbara had at first is the same in Case 1 and Case 2.
1.5 u + 14 = 1 u + 19
1.5 u - 1 u = 19 - 14
0.5 u = 5
1 u = 5 ÷ 0.5 = 10
Number of croissants that Barbara has
= 1 u + 19
= 1 x 10 + 19
= 10 + 19
= 29
Answer(s): 29