Yoko and Risa have some cupcakes each. If Yoko gives Risa 17 cupcakes, Yoko will have
67 as many cupcakes as Risa. If Yoko gives Risa 12 cupcakes, they will have an equal number of cupcakes. How many cupcakes does Yoko have at first?
|
Case 1 |
Case 2 |
|
Yoko |
Risa |
Yoko |
Risa |
Before |
6 u + 17 |
7 u - 17 |
6.5 u + 12 |
6.5 u - 12 |
Change |
- 17 |
+ 17 |
- 12 |
+ 12 |
After |
6 u |
7 u |
6.5 u |
6.5 u |
Total number of cupcakes that Yoko and Risa have
= 6 u + 7 u
= 13 u
Number of cupcakes that Yoko and Risa each has in the end is the same.
Number of cupcakes that Yoko and Risa each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u
Number of cupcakes that Yoko had at first is the same in Case 1 and Case 2.
6.5 u + 12 = 6 u + 17
6.5 u - 6 u = 17 - 12
0.5 u = 5
1 u = 5 ÷ 0.5 = 10
Number of cupcakes that Yoko has
= 6 u + 17
= 6 x 10 + 17
= 60 + 17
= 77
Answer(s): 77