Joelle and Kathy have some macarons each. If Joelle gives Kathy 13 macarons, Joelle will have
49 as many macarons as Kathy. If Joelle gives Kathy 3 macarons, they will have an equal number of macarons. How many macarons does Joelle have at first?
|
Case 1 |
Case 2 |
|
Joelle |
Kathy |
Joelle |
Kathy |
Before |
4 u + 13 |
9 u - 13 |
6.5 u + 3 |
6.5 u - 3 |
Change |
- 13 |
+ 13 |
- 3 |
+ 3 |
After |
4 u |
9 u |
6.5 u |
6.5 u |
Total number of macarons that Joelle and Kathy have
= 4 u + 9 u
= 13 u
Number of macarons that Joelle and Kathy each has in the end is the same.
Number of macarons that Joelle and Kathy each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u
Number of macarons that Joelle had at first is the same in Case 1 and Case 2.
6.5 u + 3 = 4 u + 13
6.5 u - 4 u = 13 - 3
0.5 u = 10
1 u = 10 ÷ 0.5 = 20
Number of macarons that Joelle has
= 4 u + 13
= 4 x 20 + 13
= 80 + 13
= 93
Answer(s): 93