Elyse and Jaslyn have some tarts each. If Elyse gives Jaslyn 22 tarts, Elyse will have
12 as many tarts as Jaslyn. If Elyse gives Jaslyn 2 tarts, they will have an equal number of tarts. How many tarts does Jaslyn have at first?
|
Case 1 |
Case 2 |
|
Elyse |
Jaslyn |
Elyse |
Jaslyn |
Before |
1 u + 22 |
2 u - 22 |
1.5 u + 2 |
1.5 u - 2 |
Change |
- 22 |
+ 22 |
- 2 |
+ 2 |
After |
1 u |
2 u |
1.5 u |
1.5 u |
Total number of tarts that Elyse and Jaslyn have
= 1 u + 2 u
= 3 u
Number of tarts that Elyse and Jaslyn each has in the end is the same.
Number of tarts that Elyse and Jaslyn each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u
Number of tarts that Elyse had at first is the same in Case 1 and Case 2.
1.5 u + 2 = 1 u + 22
1.5 u - 1 u = 22 - 2
0.5 u = 20
1 u = 20 ÷ 0.5 = 40
Number of tarts that Jaslyn has
= 2 u - 22
= 2 x 40 - 22
= 80 - 22
= 58
Answer(s): 58