Shiyun and Natalie have some croissants each. If Shiyun gives Natalie 18 croissants, Shiyun will have ⁵₈ as many croissants as Natalie. If Shiyun gives Natalie 4 croissants, they will have an equal number of croissants. How many croissants does Natalie have at first?

	Case 1		Case 2
	Shiyun	Natalie	Shiyun	Natalie
Before	5 u + 18	8 u - 18	6.5 u + 4	6.5 u - 4
Change	- 18	+ 18	- 4	+ 4
After	5 u	8 u	6.5 u	6.5 u

Total number of croissants that Shiyun and Natalie have
= 5 u + 8 u
= 13 u 

Number of croissants that Shiyun and Natalie each has in the end is the same.

Number of croissants that Shiyun and Natalie each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u

Number of croissants that Shiyun had at first is the same in Case 1 and Case 2.

6.5 u + 4 = 5 u + 18
6.5 u - 5 u = 18 - 4
0.5 u = 14

1 u = 14 ÷ 0.5 = 28

Number of croissants that Natalie has
= 8 u - 18
= 8 x 28 - 18
= 224 - 18
= 206

Answer(s): 206