Gillian and Yoko have some croissants each. If Gillian gives Yoko 24 croissants, Gillian will have ²₃ as many croissants as Yoko. If Gillian gives Yoko 16 croissants, they will have an equal number of croissants. How many croissants does Gillian have at first?

	Case 1		Case 2
	Gillian	Yoko	Gillian	Yoko
Before	2 u + 24	3 u - 24	2.5 u + 16	2.5 u - 16
Change	- 24	+ 24	- 16	+ 16
After	2 u	3 u	2.5 u	2.5 u

Total number of croissants that Gillian and Yoko have
= 2 u + 3 u
= 5 u 

Number of croissants that Gillian and Yoko each has in the end is the same.

Number of croissants that Gillian and Yoko each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u

Number of croissants that Gillian had at first is the same in Case 1 and Case 2.

2.5 u + 16 = 2 u + 24
2.5 u - 2 u = 24 - 16
0.5 u = 8

1 u = 8 ÷ 0.5 = 16

Number of croissants that Gillian has
= 2 u + 24
= 2 x 16 + 24
= 32 + 24
= 56

Answer(s): 56