Min and Hazel have some tarts each. If Min gives Hazel 13 tarts, Min will have
12 as many tarts as Hazel. If Min gives Hazel 5 tarts, they will have an equal number of tarts. How many tarts does Min have at first?
| |
Case 1 |
Case 2 |
| |
Min |
Hazel |
Min |
Hazel |
| Before |
1 u + 13 |
2 u - 13 |
1.5 u + 5 |
1.5 u - 5 |
| Change |
- 13 |
+ 13 |
- 5 |
+ 5 |
| After |
1 u |
2 u |
1.5 u |
1.5 u |
Total number of tarts that Min and Hazel have
= 1 u + 2 u
= 3 u
Number of tarts that Min and Hazel each has in the end is the same.
Number of tarts that Min and Hazel each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u
Number of tarts that Min had at first is the same in Case 1 and Case 2.
1.5 u + 5 = 1 u + 13
1.5 u - 1 u = 13 - 5
0.5 u = 8
1 u = 8 ÷ 0.5 = 16
Number of tarts that Min has
= 1 u + 13
= 1 x 16 + 13
= 16 + 13
= 29
Answer(s): 29
