Linda and Raeann have some croissants each. If Linda gives Raeann 24 croissants, Linda will have ²₃ as many croissants as Raeann. If Linda gives Raeann 9 croissants, they will have an equal number of croissants. How many croissants does Raeann have at first?

	Case 1		Case 2
	Linda	Raeann	Linda	Raeann
Before	2 u + 24	3 u - 24	2.5 u + 9	2.5 u - 9
Change	- 24	+ 24	- 9	+ 9
After	2 u	3 u	2.5 u	2.5 u

Total number of croissants that Linda and Raeann have
= 2 u + 3 u
= 5 u 

Number of croissants that Linda and Raeann each has in the end is the same.

Number of croissants that Linda and Raeann each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u

Number of croissants that Linda had at first is the same in Case 1 and Case 2.

2.5 u + 9 = 2 u + 24
2.5 u - 2 u = 24 - 9
0.5 u = 15

1 u = 15 ÷ 0.5 = 30

Number of croissants that Raeann has
= 3 u - 24
= 3 x 30 - 24
= 90 - 24
= 66

Answer(s): 66