Gwen and Esther have some wafers each. If Gwen gives Esther 23 wafers, Gwen will have
16 as many wafers as Esther. If Gwen gives Esther 10 wafers, they will have an equal number of wafers. How many wafers does Esther have at first?
|
Case 1 |
Case 2 |
|
Gwen |
Esther |
Gwen |
Esther |
Before |
1 u + 23 |
6 u - 23 |
3.5 u + 10 |
3.5 u - 10 |
Change |
- 23 |
+ 23 |
- 10 |
+ 10 |
After |
1 u |
6 u |
3.5 u |
3.5 u |
Total number of wafers that Gwen and Esther have
= 1 u + 6 u
= 7 u
Number of wafers that Gwen and Esther each has in the end is the same.
Number of wafers that Gwen and Esther each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u
Number of wafers that Gwen had at first is the same in Case 1 and Case 2.
3.5 u + 10 = 1 u + 23
3.5 u - 1 u = 23 - 10
0.5 u = 13
1 u = 13 ÷ 0.5 = 26
Number of wafers that Esther has
= 6 u - 23
= 6 x 26 - 23
= 156 - 23
= 133
Answer(s): 133