Wendy and Ivory have some biscuits each. If Wendy gives Ivory 17 biscuits, Wendy will have
12 as many biscuits as Ivory. If Wendy gives Ivory 10 biscuits, they will have an equal number of biscuits. How many biscuits does Wendy have at first?
|
Case 1 |
Case 2 |
|
Wendy |
Ivory |
Wendy |
Ivory |
Before |
1 u + 17 |
2 u - 17 |
1.5 u + 10 |
1.5 u - 10 |
Change |
- 17 |
+ 17 |
- 10 |
+ 10 |
After |
1 u |
2 u |
1.5 u |
1.5 u |
Total number of biscuits that Wendy and Ivory have
= 1 u + 2 u
= 3 u
Number of biscuits that Wendy and Ivory each has in the end is the same.
Number of biscuits that Wendy and Ivory each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u
Number of biscuits that Wendy had at first is the same in Case 1 and Case 2.
1.5 u + 10 = 1 u + 17
1.5 u - 1 u = 17 - 10
0.5 u = 7
1 u = 7 ÷ 0.5 = 14
Number of biscuits that Wendy has
= 1 u + 17
= 1 x 14 + 17
= 14 + 17
= 31
Answer(s): 31