Raeann and Kimberly have some cookies each. If Raeann gives Kimberly 17 cookies, Raeann will have ¹₂ as many cookies as Kimberly. If Raeann gives Kimberly 8 cookies, they will have an equal number of cookies. How many cookies does Raeann have at first?

	Case 1		Case 2
	Raeann	Kimberly	Raeann	Kimberly
Before	1 u + 17	2 u - 17	1.5 u + 8	1.5 u - 8
Change	- 17	+ 17	- 8	+ 8
After	1 u	2 u	1.5 u	1.5 u

Total number of cookies that Raeann and Kimberly have
= 1 u + 2 u
= 3 u 

Number of cookies that Raeann and Kimberly each has in the end is the same.

Number of cookies that Raeann and Kimberly each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u

Number of cookies that Raeann had at first is the same in Case 1 and Case 2.

1.5 u + 8 = 1 u + 17
1.5 u - 1 u = 17 - 8
0.5 u = 9

1 u = 9 ÷ 0.5 = 18

Number of cookies that Raeann has
= 1 u + 17
= 1 x 18 + 17
= 18 + 17
= 35

Answer(s): 35