Xuan and Emma have some cupcakes each. If Xuan gives Emma 7 cupcakes, Xuan will have
34 as many cupcakes as Emma. If Xuan gives Emma 5 cupcakes, they will have an equal number of cupcakes. How many cupcakes does Xuan have at first?
|
Case 1 |
Case 2 |
|
Xuan |
Emma |
Xuan |
Emma |
Before |
3 u + 7 |
4 u - 7 |
3.5 u + 5 |
3.5 u - 5 |
Change |
- 7 |
+ 7 |
- 5 |
+ 5 |
After |
3 u |
4 u |
3.5 u |
3.5 u |
Total number of cupcakes that Xuan and Emma have
= 3 u + 4 u
= 7 u
Number of cupcakes that Xuan and Emma each has in the end is the same.
Number of cupcakes that Xuan and Emma each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u
Number of cupcakes that Xuan had at first is the same in Case 1 and Case 2.
3.5 u + 5 = 3 u + 7
3.5 u - 3 u = 7 - 5
0.5 u = 2
1 u = 2 ÷ 0.5 = 4
Number of cupcakes that Xuan has
= 3 u + 7
= 3 x 4 + 7
= 12 + 7
= 19
Answer(s): 19