Gem and Ivory have some wafers each. If Gem gives Ivory 26 wafers, Gem will have
58 as many wafers as Ivory. If Gem gives Ivory 7 wafers, they will have an equal number of wafers. How many wafers does Ivory have at first?
| |
Case 1 |
Case 2 |
| |
Gem |
Ivory |
Gem |
Ivory |
| Before |
5 u + 26 |
8 u - 26 |
6.5 u + 7 |
6.5 u - 7 |
| Change |
- 26 |
+ 26 |
- 7 |
+ 7 |
| After |
5 u |
8 u |
6.5 u |
6.5 u |
Total number of wafers that Gem and Ivory have
= 5 u + 8 u
= 13 u
Number of wafers that Gem and Ivory each has in the end is the same.
Number of wafers that Gem and Ivory each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u
Number of wafers that Gem had at first is the same in Case 1 and Case 2.
6.5 u + 7 = 5 u + 26
6.5 u - 5 u = 26 - 7
0.5 u = 19
1 u = 19 ÷ 0.5 = 38
Number of wafers that Ivory has
= 8 u - 26
= 8 x 38 - 26
= 304 - 26
= 278
Answer(s): 278
