Cindy and Marion have some biscuits each. If Cindy gives Marion 32 biscuits, Cindy will have ⁵₈ as many biscuits as Marion. If Cindy gives Marion 3 biscuits, they will have an equal number of biscuits. How many biscuits does Marion have at first?

	Case 1		Case 2
	Cindy	Marion	Cindy	Marion
Before	5 u + 32	8 u - 32	6.5 u + 3	6.5 u - 3
Change	- 32	+ 32	- 3	+ 3
After	5 u	8 u	6.5 u	6.5 u

Total number of biscuits that Cindy and Marion have
= 5 u + 8 u
= 13 u 

Number of biscuits that Cindy and Marion each has in the end is the same.

Number of biscuits that Cindy and Marion each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u

Number of biscuits that Cindy had at first is the same in Case 1 and Case 2.

6.5 u + 3 = 5 u + 32
6.5 u - 5 u = 32 - 3
0.5 u = 29

1 u = 29 ÷ 0.5 = 58

Number of biscuits that Marion has
= 8 u - 32
= 8 x 58 - 32
= 464 - 32
= 432

Answer(s): 432