Penelope and Shannon have some tarts each. If Penelope gives Shannon 20 tarts, Penelope will have
25 as many tarts as Shannon. If Penelope gives Shannon 9 tarts, they will have an equal number of tarts. How many tarts does Shannon have at first?
|
Case 1 |
Case 2 |
|
Penelope |
Shannon |
Penelope |
Shannon |
Before |
2 u + 20 |
5 u - 20 |
3.5 u + 9 |
3.5 u - 9 |
Change |
- 20 |
+ 20 |
- 9 |
+ 9 |
After |
2 u |
5 u |
3.5 u |
3.5 u |
Total number of tarts that Penelope and Shannon have
= 2 u + 5 u
= 7 u
Number of tarts that Penelope and Shannon each has in the end is the same.
Number of tarts that Penelope and Shannon each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u
Number of tarts that Penelope had at first is the same in Case 1 and Case 2.
3.5 u + 9 = 2 u + 20
3.5 u - 2 u = 20 - 9
0.5 u = 11
1 u = 11 ÷ 0.5 = 22
Number of tarts that Shannon has
= 5 u - 20
= 5 x 22 - 20
= 110 - 20
= 90
Answer(s): 90