Nicole and Marion have some shortbreads each. If Nicole gives Marion 15 shortbreads, Nicole will have
29 as many shortbreads as Marion. If Nicole gives Marion 10 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Nicole have at first?
|
Case 1 |
Case 2 |
|
Nicole |
Marion |
Nicole |
Marion |
Before |
2 u + 15 |
9 u - 15 |
5.5 u + 10 |
5.5 u - 10 |
Change |
- 15 |
+ 15 |
- 10 |
+ 10 |
After |
2 u |
9 u |
5.5 u |
5.5 u |
Total number of shortbreads that Nicole and Marion have
= 2 u + 9 u
= 11 u
Number of shortbreads that Nicole and Marion each has in the end is the same.
Number of shortbreads that Nicole and Marion each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of shortbreads that Nicole had at first is the same in Case 1 and Case 2.
5.5 u + 10 = 2 u + 15
5.5 u - 2 u = 15 - 10
0.5 u = 5
1 u = 5 ÷ 0.5 = 10
Number of shortbreads that Nicole has
= 2 u + 15
= 2 x 10 + 15
= 20 + 15
= 35
Answer(s): 35