Natalie and Risa have some tarts each. If Natalie gives Risa 25 tarts, Natalie will have
58 as many tarts as Risa. If Natalie gives Risa 20 tarts, they will have an equal number of tarts. How many tarts does Natalie have at first?
|
Case 1 |
Case 2 |
|
Natalie |
Risa |
Natalie |
Risa |
Before |
5 u + 25 |
8 u - 25 |
6.5 u + 20 |
6.5 u - 20 |
Change |
- 25 |
+ 25 |
- 20 |
+ 20 |
After |
5 u |
8 u |
6.5 u |
6.5 u |
Total number of tarts that Natalie and Risa have
= 5 u + 8 u
= 13 u
Number of tarts that Natalie and Risa each has in the end is the same.
Number of tarts that Natalie and Risa each has in the end in Case 2
= 13 u ÷ 2
= 6.5 u
Number of tarts that Natalie had at first is the same in Case 1 and Case 2.
6.5 u + 20 = 5 u + 25
6.5 u - 5 u = 25 - 20
0.5 u = 5
1 u = 5 ÷ 0.5 = 10
Number of tarts that Natalie has
= 5 u + 25
= 5 x 10 + 25
= 50 + 25
= 75
Answer(s): 75