Elyse and Abi have some shortbreads each. If Elyse gives Abi 13 shortbreads, Elyse will have ¹₆ as many shortbreads as Abi. If Elyse gives Abi 11 shortbreads, they will have an equal number of shortbreads. How many shortbreads does Elyse have at first?

	Case 1		Case 2
	Elyse	Abi	Elyse	Abi
Before	1 u + 13	6 u - 13	3.5 u + 11	3.5 u - 11
Change	- 13	+ 13	- 11	+ 11
After	1 u	6 u	3.5 u	3.5 u

Total number of shortbreads that Elyse and Abi have
= 1 u + 6 u
= 7 u 

Number of shortbreads that Elyse and Abi each has in the end is the same.

Number of shortbreads that Elyse and Abi each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u

Number of shortbreads that Elyse had at first is the same in Case 1 and Case 2.

3.5 u + 11 = 1 u + 13
3.5 u - 1 u = 13 - 11
0.5 u = 2

1 u = 2 ÷ 0.5 = 4

Number of shortbreads that Elyse has
= 1 u + 13
= 1 x 4 + 13
= 4 + 13
= 17

Answer(s): 17