Xylia and Eva have some biscuits each. If Xylia gives Eva 24 biscuits, Xylia will have ²₃ as many biscuits as Eva. If Xylia gives Eva 20 biscuits, they will have an equal number of biscuits. How many biscuits does Xylia have at first?

	Case 1		Case 2
	Xylia	Eva	Xylia	Eva
Before	2 u + 24	3 u - 24	2.5 u + 20	2.5 u - 20
Change	- 24	+ 24	- 20	+ 20
After	2 u	3 u	2.5 u	2.5 u

Total number of biscuits that Xylia and Eva have
= 2 u + 3 u
= 5 u 

Number of biscuits that Xylia and Eva each has in the end is the same.

Number of biscuits that Xylia and Eva each has in the end in Case 2
= 5 u ÷ 2
= 2.5 u

Number of biscuits that Xylia had at first is the same in Case 1 and Case 2.

2.5 u + 20 = 2 u + 24
2.5 u - 2 u = 24 - 20
0.5 u = 4

1 u = 4 ÷ 0.5 = 8

Number of biscuits that Xylia has
= 2 u + 24
= 2 x 8 + 24
= 16 + 24
= 40

Answer(s): 40