Usha and Winnie have some wafers each. If Usha gives Winnie 16 wafers, Usha will have
12 as many wafers as Winnie. If Usha gives Winnie 4 wafers, they will have an equal number of wafers. How many wafers does Winnie have at first?
|
Case 1 |
Case 2 |
|
Usha |
Winnie |
Usha |
Winnie |
Before |
1 u + 16 |
2 u - 16 |
1.5 u + 4 |
1.5 u - 4 |
Change |
- 16 |
+ 16 |
- 4 |
+ 4 |
After |
1 u |
2 u |
1.5 u |
1.5 u |
Total number of wafers that Usha and Winnie have
= 1 u + 2 u
= 3 u
Number of wafers that Usha and Winnie each has in the end is the same.
Number of wafers that Usha and Winnie each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u
Number of wafers that Usha had at first is the same in Case 1 and Case 2.
1.5 u + 4 = 1 u + 16
1.5 u - 1 u = 16 - 4
0.5 u = 12
1 u = 12 ÷ 0.5 = 24
Number of wafers that Winnie has
= 2 u - 16
= 2 x 24 - 16
= 48 - 16
= 32
Answer(s): 32