Gwen and Yen have some biscuits each. If Gwen gives Yen 26 biscuits, Gwen will have
25 as many biscuits as Yen. If Gwen gives Yen 20 biscuits, they will have an equal number of biscuits. How many biscuits does Gwen have at first?
|
Case 1 |
Case 2 |
|
Gwen |
Yen |
Gwen |
Yen |
Before |
2 u + 26 |
5 u - 26 |
3.5 u + 20 |
3.5 u - 20 |
Change |
- 26 |
+ 26 |
- 20 |
+ 20 |
After |
2 u |
5 u |
3.5 u |
3.5 u |
Total number of biscuits that Gwen and Yen have
= 2 u + 5 u
= 7 u
Number of biscuits that Gwen and Yen each has in the end is the same.
Number of biscuits that Gwen and Yen each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u
Number of biscuits that Gwen had at first is the same in Case 1 and Case 2.
3.5 u + 20 = 2 u + 26
3.5 u - 2 u = 26 - 20
0.5 u = 6
1 u = 6 ÷ 0.5 = 12
Number of biscuits that Gwen has
= 2 u + 26
= 2 x 12 + 26
= 24 + 26
= 50
Answer(s): 50