Nicole and Fanny have some wafers each. If Nicole gives Fanny 29 wafers, Nicole will have
27 as many wafers as Fanny. If Nicole gives Fanny 3 wafers, they will have an equal number of wafers. How many wafers does Fanny have at first?
|
Case 1 |
Case 2 |
|
Nicole |
Fanny |
Nicole |
Fanny |
Before |
2 u + 29 |
7 u - 29 |
4.5 u + 3 |
4.5 u - 3 |
Change |
- 29 |
+ 29 |
- 3 |
+ 3 |
After |
2 u |
7 u |
4.5 u |
4.5 u |
Total number of wafers that Nicole and Fanny have
= 2 u + 7 u
= 9 u
Number of wafers that Nicole and Fanny each has in the end is the same.
Number of wafers that Nicole and Fanny each has in the end in Case 2
= 9 u ÷ 2
= 4.5 u
Number of wafers that Nicole had at first is the same in Case 1 and Case 2.
4.5 u + 3 = 2 u + 29
4.5 u - 2 u = 29 - 3
0.5 u = 26
1 u = 26 ÷ 0.5 = 52
Number of wafers that Fanny has
= 7 u - 29
= 7 x 52 - 29
= 364 - 29
= 335
Answer(s): 335