Raeann and Tina have some cupcakes each. If Raeann gives Tina 38 cupcakes, Raeann will have
56 as many cupcakes as Tina. If Raeann gives Tina 10 cupcakes, they will have an equal number of cupcakes. How many cupcakes does Tina have at first?
|
Case 1 |
Case 2 |
|
Raeann |
Tina |
Raeann |
Tina |
Before |
5 u + 38 |
6 u - 38 |
5.5 u + 10 |
5.5 u - 10 |
Change |
- 38 |
+ 38 |
- 10 |
+ 10 |
After |
5 u |
6 u |
5.5 u |
5.5 u |
Total number of cupcakes that Raeann and Tina have
= 5 u + 6 u
= 11 u
Number of cupcakes that Raeann and Tina each has in the end is the same.
Number of cupcakes that Raeann and Tina each has in the end in Case 2
= 11 u ÷ 2
= 5.5 u
Number of cupcakes that Raeann had at first is the same in Case 1 and Case 2.
5.5 u + 10 = 5 u + 38
5.5 u - 5 u = 38 - 10
0.5 u = 28
1 u = 28 ÷ 0.5 = 56
Number of cupcakes that Tina has
= 6 u - 38
= 6 x 56 - 38
= 336 - 38
= 298
Answer(s): 298